Whoever gives the best answer has the biggest penis.
|-1/(x+3)| >= (1/2)
i.e.
Find x when the absolute value of (-1/(x+3)) is greater than or equal to 1/2.
Peace--1/(x + 3) ≥ 1/2
-2 ≥ x + 3
-5 ≥
The questions is to find the radius of a wonder building. It is basically just an arc. It says the span is 30 meters and the height is 10. I drew a line along the base of the arc and made that my x ax
Why is x^3 + 2x + 3 irreducible over Z5[x]?
And how can I express it as a product of polynomials?-If x^3 + 2x + 3 factors nontrivially in Z_5[x], one of the factors has to have degree 1.(The only non
Multiply both sides by q:
q(7q - 2) = 4/q * q
7q² - 2q = 4
Then, bring 4 to the left:
7q² - 2q - 4 = 0
Since the expression is not factorable, use quadratic formula, letting:
a = 7
b = -2
c = -4
I am going in AP Calc BC next year and I wanted a good head start. I am reviewing the AP Calculus Prep books as well as videos on khanacademy.org. What else should I do?
One more thing, I have NOT tak
Ive got a maths question and it says:
1 litre of paint covers an area of 20 metres squared. Work out the volume of paint needed to cover the wall. Give your answer in millilitres.
The area of the wa
I dont understand how to do this.
Help, please? :|-This is actually not true. Unless you wrote down the problem wrong, simplifying the more complex part of this relation simplifies to -2*cot(x)^2. I w
You would first subtract the 6, then use logarithms. So,
3^x+6=370
3^x=364
Log(3)x=Log(364)
x=Log(364)/Log3
x=5.378
Make sense?-3^x = 361subtract 6 from both sides
logbase3 x = logbase3 361log base
the graph of x^2 y + xy^2 = 6
dy/dx= -(2xy+y^2)/(x^2+2xy)
at one point, the curve is horizontal. find the exact coordinate of that point
any help would be greatly appreciated!!!-Since I concur with
Simplify the trigonometric expression.
sin^3(x)+cos^2(x)sin(x)
Simplify the trigonometric expression.
1+cot(x)/csc(x)
first person to give me both correct answers will get best answer.-first one, fa
x^4+4=0
=>x^4+4x^2+4=4x^2
=>(x^2+2)^2=4x^2
=>x^2+2=2x,-2x
=>x^2+2x+2=0 &x^2-2x+2=0
by using the formule of solving a quadratic equation (ax^2+bx+c=0)
is1/2a times-b+square root of(b^-4ac)1/2a time
