A series combination of two resistors, R1 = 9 Ω and R2 = 5.3 Ω, is connected to a 9 V battery.

A series combination of two resistors, R1 = 9 Ω and R2 = 5.3 Ω, is connected to a 9 V battery.

The first thing we had to do was:
a) Calculate the equivalent resistance of the circuit. It was 14.3 Ω

I do not know how to do B. Please show work. Thanks.

b) What is the potential difference across each resistor?
Potential Difference across R1:
Potential Difference across R2:

I = 9/14.3 => VR1 = (9/14.3)*9 = 5.66V VR2=(9/14.3)*5.3=3.34 => 5.66+3.34=9V