Distance = average velocity * time
Average velocity = ½ * (0 + 40) = 20 m/s
Distance = 20 * (40 ÷ 9.8)
5. You throw an orange straight up into the air. When you release the orange it is 1.5 m above the ground. The orange reaches a maximum height of 21.1 m. With what velocity did you release the orange?
As the ball traveled upward, its velocity decreased 9.8 m/s each second. The final velocity at the maximum height is always 0 m/s.
displacement = Final position – Initial position = 21.1 – 1.5 = 19.6 m
acceleration = -9.8 m/s^2
Final velocity = 0 m/s
Since we do not know the time,
Final velocity^2 – Initial velocity^2 = (2 * -9.8 * 19.6)
6. Solve the following system for k, w and n.
Solve the 1st 2 equations for k, and set the 2 equations for k equal to each other
k + w + n = 4
k = 4 – w – n
k – 2w – n = 1
k = 1 + 2w + n
4 – w – n = 1 + 2w + n
Solve the 2nd 2 equations for k, and set the 2 equations for k equal to each other
k = 1 + 2w + n
2k – w – 2n = -1
2k = -1 + w + 2n
k = -½ + w/2 + n
1 + 2w + n = -½ + w/2 + n
Then solve these 2 equations for n and find w
7. A plate slides across a table at 6 m/s. The plate lands 3 m away (horizontally) from the edge of the table. How high is the table? How long was the plate airborne?
During the time that the plate falls to the floor, the plate also moved 3 m horizontally. The horizontal velocity remains constant, but the vertical velocity increases 9.8 m/s each second.
Horizontal distance = Horizontal velocity * time
3 = 6 * t, solve for t, and use in equation below!
Vertical distance = ½ * 9.8 * t^2