Two point charges of +2 µC and +6 µC repel each other with a force of 12 N.if each is given an additional charge of -4 µC,then what will be the new force?
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Force is proportional to the product of charges.
Initial product of charges = (2)(6) = 12 µC^2
New product of charges = (2-4)(6-4) = (-2)(2) = -4 µC^2
New force/original force = -4/12 = -1/3
New force = -12/3 = -4 N
Negative sign shows that the charges attract each other.
Ans: Charges will attract each other with a force of 4 N
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Initial product of charges = (2)(6) = 12 µC^2
New product of charges = (2-4)(6-4) = (-2)(2) = -4 µC^2
New force/original force = -4/12 = -1/3
New force = -12/3 = -4 N
Negative sign shows that the charges attract each other.
Ans: Charges will attract each other with a force of 4 N
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Coulomb's law : F = kQ1. Q2/r^2
-----> 12 = k 2. 6/r^2
-----> F' = k (2-4)(6-4)/r^2
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12/F' = 12/4 ---> F' = 4 N
-----> 12 = k 2. 6/r^2
-----> F' = k (2-4)(6-4)/r^2
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12/F' = 12/4 ---> F' = 4 N