One object of 0.5 kg falls from a height of 10 m. Which is its momentum immediately before reaching the ground?
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v = √(2*g*y) = 14 m/s
P = m*v = .5*14 = 7 kg∙m/s down
P = m*v = .5*14 = 7 kg∙m/s down
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people will solve the question for you , but the question itself was made to make you understand something. Energy is conserved, friend. Apply the conservation of total mechanical energy (since it the free fall case) and you will get the answer. Total energy before falling 10m = total energy after (or just falling by) falling 10m. Good luck with physics !