The plane of loop perpendicular to the magnetic field
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The plane of loop perpendicular to the magnetic field

[From: ] [author: ] [Date: 11-07-08] [Hit: ]
87 = 9.ΔΦ = Φ’ - Φ=9.5 x 10^-4 - 1.1 x 10^-3= 1.......
The plane of loop with dimensions 10 cm × 11 cm is initially perpendicular to a uniform 0.1 T magnetic field. Find the change in flux through the loop if it is turned through 150 degrees about an axis perpendicular to the field lines.

?? Wb

-
Area A = 10 x 11 = 110 cm^2 = 0.011 m^2
Magnetic field B = 0.1 T
The initial flux:
Φ = B * A cos 0
= 0.1 * 0.011 * 1 = 1.1 x 10^-3 Wb
The final Flux :
Φ' = B * A * lcos 150l
= 0.1 * 0.011 * 0.87
= 9.5 x 10^-4 Wb

ΔΦ = Φ’ - Φ
=9.5 x 10^-4 - 1.1 x 10^-3
= 1.5 x 10^-4 Wb
1
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