Physics help- A series RC circuit has a time constant of 0.910 s

A series RC circuit has a time constant of 0.910 s. The battery has an emf of 47.0 V, and the maximum current in the circuit is 500 mA.
(a) What is the value of the capacitance?
______ F

(b) What is the charge stored in the capacitor 1.92 s after the switch is closed?
______ C

I have the equation for RC circuits but still dont know how to use it with this question. please help!!

There is a battery so assume the capacitor is being CHARGED, not discharged.

(a)
On charge, maximum current is at t = 0 and equals V / R
So 47V / R = 0.5 A
R = 94 ohm
T = RC = 0.910 s
So C = 0.910s / 94 ohm = 0.00968 F

(b)
Voltage on charge is V = Vo(1 - e^(-t/RC))
At t = 1.92s,
V = 47V (1 - e^(-1.92/0.910)) = 47*(1 - 0.12125) V = 41.3V
so at t = 1.92s
charge Q = CV = .00968F * 41.3V = 0.400 C