Someone please explain this to me... I dont know why I'm confused. Why is the equation for velocity for a free falling object v = gt if it is being dropped from something. g has units of m/s and t has units of s. So it seems v would have units of m/s^2 which would be acceleration.
I understand that acceleration would equal velocity until terminal velocity is reached since there is no initial velocity. But still the units m/s^s doesn't make sense to me.
I understand that acceleration would equal velocity until terminal velocity is reached since there is no initial velocity. But still the units m/s^s doesn't make sense to me.
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By SI conventions,
acceleration (due to gravity) is measured in units of meter per square second (m / (s^2)).
time is measured in seconds (s).
velocity is measured in meters per second (m/s)
perform dimensional analysis:
v = g*t
(m/s) = (m/s^2) * s = m/s
acceleration is defined as the change in velocity with respect to time ( a = dv/dt).
gravitational acceleration is (nearly) constant on earth with a value of 9.81 m/s^2.
so, gravitational acceleration causes the change in velocity (from rest) of the object in question.
acceleration (due to gravity) is measured in units of meter per square second (m / (s^2)).
time is measured in seconds (s).
velocity is measured in meters per second (m/s)
perform dimensional analysis:
v = g*t
(m/s) = (m/s^2) * s = m/s
acceleration is defined as the change in velocity with respect to time ( a = dv/dt).
gravitational acceleration is (nearly) constant on earth with a value of 9.81 m/s^2.
so, gravitational acceleration causes the change in velocity (from rest) of the object in question.