A car starts from rest and has a constant acceleration of 3.0m/s2. if it travels 33m

a car starts from rest and has a constant acceleration of 3.0m/s2. if it travels 33m, how long will it take to complete the motion?

Ok so ...
VI=0
VF=?
A=3.0
D=33
you are solving for T.

use D=(VI)(T)+(.5)(A)(T^2)
then plug in values
33=(0)(T) + (.5)(A)(T^2)
33=(.5)(3)(T^2)
33=1.5T^2
33/1.5=T^2
22=T^2
Square root both
radical22=T
T=~4.6904s

we use the equation of motion:

distance traveled = v0 t + 1/2 a t^2

where v0 is the initial velocity, here that is zero
t=time elapsed
a=accel = 3m/s/s


so we have

33m = 0 + 1/2 x 3m/s/s t^2

22=t^2

t =4.7s and this is the time required to cover the 33m

t = √[2x/a] = √[2*33/3] = 4.69 sec