Help in finding magnitude of magnetic field
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Help in finding magnitude of magnetic field

[From: ] [author: ] [Date: 11-12-29] [Hit: ]
6 x 10^-18/ 9.or Im missing something here?-Yes you are missing the value of q (the charge of an electron) which is equal to 1.Other then that think youve got it right.-Velocity is v and charge is q.B= 5.......
I'm having a little trouble understanding where exactly do I plug in the numbers and I don't know if I'm doing the problem right hope you can help. Thanks.

An electron moves north at a velocity of 9.8 x 10^4m/s and has a magnetic force of 5.6 x 10^-18 N west exerted on it. If the magnetic field points upward, what is the magnitude of the magnetic field?

I know the equation is B= Fmagnetic/ qv

the velocity is the qv right?
so would putting the equation like this be correct?
B= 5.6 x 10^-18/ 9.8 x 10^4

or I'm missing something here?

-
Yes you are missing the value of q (the charge of an electron) which is equal to 1.602e-19 C

Other then that think you've got it right.

-
Velocity is v and charge is q.

B= 5.6 x 10^-18/ ( 1.6 x10^-19* 9.8 x 10^4)

B = 0.00036 tesla.
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