Conservation of momentum
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Conservation of momentum

[From: ] [author: ] [Date: 12-03-31] [Hit: ]
12 kg, initially at rest on a level frictionless surface.The bullet passes through the block and emerges with its speed reduced to 122 m/s..00425*(375 - 122) = 1.Vb = 0.......
A 4.25 g bullet traveling horizontally with a velocity of magnitude 375 m/s is fired
into a wooden block with mass 1.12 kg, initially at rest on a level frictionless surface.
The bullet passes through the block and emerges with its speed reduced to 122 m/s.
How fast is the block moving just after the bullet emerges from it

-
dP1 = dP2
.00425*(375 - 122) = 1.12*Vb

Vb = 0.96 m/s
1
keywords: Conservation,momentum,of,Conservation of momentum
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