If the current is uniformly distributed everywhere, does this mean that the electric field also is ?
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In most cases it is true 1.suppose there is a wire and constt. Current is flowing through it but dist. Between terminals is very large then fd. Will be nonuniform.
2.if medium is changing continously then fd. Will be non uniform.
3.surface or wire should have no resistence.
2.if medium is changing continously then fd. Will be non uniform.
3.surface or wire should have no resistence.
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No. Here's an example.
Take a 1m length of wire of resistance 1Ω, and a 1m length of different wire, resistance 2Ω.
Connect these in series to a 30V supply.
Voltage across 1Ω wire = 10 V (e.g. from potential divider formula)
Electric field across 1Ω wire = V/d = 10 V/m
Voltage across 2Ω wire = 20 V
Electric field across 2Ω wire = 20 V/m
So the electric fields are different in the 2 wires, but the SAME current (10A) flows through both wires.
Take a 1m length of wire of resistance 1Ω, and a 1m length of different wire, resistance 2Ω.
Connect these in series to a 30V supply.
Voltage across 1Ω wire = 10 V (e.g. from potential divider formula)
Electric field across 1Ω wire = V/d = 10 V/m
Voltage across 2Ω wire = 20 V
Electric field across 2Ω wire = 20 V/m
So the electric fields are different in the 2 wires, but the SAME current (10A) flows through both wires.