A cube of gold has a mass of .827g and an edge of 3.5x10^-1 cm
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A cube of gold has a mass of .827g and an edge of 3.5x10^-1 cm

[From: ] [author: ] [Date: 12-04-13] [Hit: ]
019289*10^3 g/cm^3 = 19.ρ = m/V = .827 g / (.35 cm)³ = 19.......
What is its density?

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Volume of cube = (3.5)^3*10^-3 cm^3 = 42.875*10^-3 cm^3
Mass = 0.827g
density = mass/volume = 0.827/42.875*10^-3 = 0.019289*10^3 g/cm^3 = 19.3 g/cm^3

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Density = mass/volume:

ρ = m/V = .827 g / (.35 cm)³ = 19.3 g/cm³
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