Calculate the rms speed of the carbon dioxide molecules in the air if the temperature is 15.0 °C. Note: The
mass of the carbon dioxide molecule is 44.01 u.
I'm confused about how to use 44.01 u in the problem.
The equation i used was rms speed = sqrt 3rt/m
I think I'm calculating the mass wrong. An explanation would be greatly appreciated
The correct answer is : 404 m/s
mass of the carbon dioxide molecule is 44.01 u.
I'm confused about how to use 44.01 u in the problem.
The equation i used was rms speed = sqrt 3rt/m
I think I'm calculating the mass wrong. An explanation would be greatly appreciated
The correct answer is : 404 m/s
-
The equation is √ (3kT / m)
k = Boltzmann's constant = 1.38E-23 joule/K;
T = temperature in Kelvin degrees = 273 + 15= 288 K;
m = is the mass of one molecule of the gas = 44 x 1.6727E-27 Kg;
1.672E-27 Kg (good approximation) is the weight of a single a.m.u. (atomic mass unit);
44 is molecular weight of CO2.
Molecular Speed (CO2) = √ (3 x 1.38E-23 x 288 / 44 x 1.672E-27) = 402 m/sec.
k = Boltzmann's constant = 1.38E-23 joule/K;
T = temperature in Kelvin degrees = 273 + 15= 288 K;
m = is the mass of one molecule of the gas = 44 x 1.6727E-27 Kg;
1.672E-27 Kg (good approximation) is the weight of a single a.m.u. (atomic mass unit);
44 is molecular weight of CO2.
Molecular Speed (CO2) = √ (3 x 1.38E-23 x 288 / 44 x 1.672E-27) = 402 m/sec.