A car is traveling at 21.0 m/s. It slows to a stop at a constant rate of 5.00s. How far does the car travel during those 5.00 seconds before it stops?
I got lost on the question whenever it said it slowed to a stop at a constant rate of 5.00.
If someone could explain this to be I would be extremely grateful.
Or at least show me how to set it up or something.
Thank you.
I got lost on the question whenever it said it slowed to a stop at a constant rate of 5.00.
If someone could explain this to be I would be extremely grateful.
Or at least show me how to set it up or something.
Thank you.
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Constant acceleration a = (vf - vi) / t
vf = 0, vi = 21 m/s, t = 5s
so a = -21 / 5 m/s^2 = -4.2 m/s^2
Distance travelled s = vi*t + 0.5*a*t^2
s = 21*5 + 0.5*-4.2*5^2 m = 105m - 52.5m
s = 52.5m
vf = 0, vi = 21 m/s, t = 5s
so a = -21 / 5 m/s^2 = -4.2 m/s^2
Distance travelled s = vi*t + 0.5*a*t^2
s = 21*5 + 0.5*-4.2*5^2 m = 105m - 52.5m
s = 52.5m