Assuming that the earth is spherical, and its radius is 6.38x10^3 km and its mass is 5.98x10^24 kg.
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Assuming that the earth is spherical, and its radius is 6.38x10^3 km and its mass is 5.98x10^24 kg.

[From: ] [author: ] [Date: 12-06-27] [Hit: ]
the mass is given -> convert to grams = 5.the volume for a sphere is 4/3 * pi * r^3 = 4/3 * pi * (6.38*10^8 cm)^3 = 1.density = 5.98x10^27 / 1.density = 5.......
Assuming that the earth is spherical, and its radius is 6.38x10^3 km and its mass is 5.98x10^24 kg, calculate the average of the earth in g/cm^3.

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density = mass/ volume

the mass is given -> convert to grams = 5.98x10^27 grams

the volume for a sphere is 4/3 * pi * r^3 = 4/3 * pi * (6.38*10^8 cm)^3 = 1.08780399 × 10^27 cm^3

density = 5.98x10^27 / 1.08780399 × 10^27

density = 5.4973 g/cm^3

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Thank you very much! =))) But you forgot to convert the radius=6.38x10^3 km to cm^3

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