If a net force of 25 N is exerted over a distance of 4 m to the right on a 2 kg mass initially at rest and moves it, what is the final velocity of the object?
v = _____ m/s
A. 20
B. 14
C. 10
D. 7
v = _____ m/s
A. 20
B. 14
C. 10
D. 7
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supposing no friction etc....
the amount of work done on the mass: E = force x distance = 100 joule.
This has gone all up in motion energy: E = 1/2 x mass x speed^2
100 = 1/2 * 2kg * speed^2
So speed = sqrt(100) = 10 m/s --> C
the amount of work done on the mass: E = force x distance = 100 joule.
This has gone all up in motion energy: E = 1/2 x mass x speed^2
100 = 1/2 * 2kg * speed^2
So speed = sqrt(100) = 10 m/s --> C