If a block of wood has a density of 580 Kg/m^3 and is placed in a fluid with density 1.2 g/cm^3.

If a block of wood has a density of 580 Kg/m^3 and is placed in a fluid with density 1.2 g/cm^3. What is the mass that is located above the fluid if the block is 25 cm * 25 cm * 25 cm?

Please be clear and concise.

Lets do some unit conversion. 580 Kg/m^3 = 0.58 g/cm^3. The mass of the block is 25^3 * 0.58g/cm^3 = 9062.5g
The buoyancy force is 1.2g/cm^3 * V g which must be equal to the gravitational force due to the block = 9062.5 g
Here V is the volume of the portion of the block submerged in the fluid. So V = 9062.5 / 1.2 = 7552.083 cm^3.
The portion of the block that is above the fluid is 25^3 cm^3 - 7552.083 cm^3 = 8072.92 cm^3

Now the mass of this portion is 8072.92 cm^3 * 0.58g/cm^3 = 4682.29g