You drive a car 7h at 47km/h, then 7 h at 63km/h. what is your average velocity

I find these questions very hard !

Average velocity is total distance divided by time.

329 km + 441 km = 770 km

v = s/t = 770 km / 14 h = 55 km/h

Since the time periods are equal the average is (47 +63) / 2 = 55 km/h.
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Average is total distance/ total time = 7( 47 + 63) / 14 = 55 km/h
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For the one who has thumbed down my answer :


Suppose that (v1, t1), (v2, t2), (v3, t3), (v4, t4), are the velocities and respective times.

Average velocity is {v1t1+ v2t2 + v3t3 + v4t4} / {t1 + t2 + t3 + t4}

If time periods are equal then the above reduces to
t (v1+ v2 + v3 + v4 } / 4 t =(v1+ v2 + v3 + v4) / 4
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In the given problem there are only two time periods which are equal to each other.
Hence the answer is (v1+ v2) /2

V=D/T
so find your distance and your time.
well for time youd add 7 + 7 and that'd give you a total of 14 hours
and for your distance, remember the distance formula?
your distance formula is d= v*t
so you have your velocity and times which are 7 * 47 PLUS 7 * 63 = 770
now you have both your total time and total distance. now divide them!
770/14 = 55.
so 55 km/h is ur answer!