Calculate the work done by the applied force accelerating a 2.0 kg object at 3.0 m/s^2 over a distance of 4.0 m if there was a 2.5 N frictional force of resistance. How much work was done by the frictional force?
Proper significant digits please.
Proper significant digits please.
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Resultant force is mass x acceleration:
F - F_fric = ma = 2.0 x 3.0 = 6.0 N
F_fric = 2.5 N
Rearrange and input F_fric:
F = 6.0 + F_fric = 6.0 + 2.5 = 8.5 N
Work done is force x distance, input d=4.0 m and F=8.5 N:
W = Fd = 8.5 x 4.0 = 34 J
Hope this is useful.
F - F_fric = ma = 2.0 x 3.0 = 6.0 N
F_fric = 2.5 N
Rearrange and input F_fric:
F = 6.0 + F_fric = 6.0 + 2.5 = 8.5 N
Work done is force x distance, input d=4.0 m and F=8.5 N:
W = Fd = 8.5 x 4.0 = 34 J
Hope this is useful.
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work done by friction = F_fric x d = 2.5 x 4.0 = 10 J
Hope you read this.
Hope you read this.
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