A 7.6 resistor and a 6.4 resistor are connected in series with a battery. The current across the 7.6 resistor is measured as 0.25 A. Find the potential difference across the battery.
______ V
______ V
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E=IR
E76= 0.25*7.6= 1.9v
E64= 0.25*6.4= 1.6v
Eo= 1.9+1.6= 3.5[V] ( Battery voltage )
E76= 0.25*7.6= 1.9v
E64= 0.25*6.4= 1.6v
Eo= 1.9+1.6= 3.5[V] ( Battery voltage )