[From: Physics] [author: ] [Date: 01-07] [Hit: ]

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Andrew Smith say: Momentum is conserved
m1 v1 + m2 v2 = (m1 +m2)V
v2 =( (m1+m2) V - m1 v1 ) / m2
= ( ( 1510 + 2240)*5.89 - ( 1510 * -13.2) ) / 2240 ~= 18.8 m/s North
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oubaas say: Momentum conservation shall apply :
V*(m1+m2) = V1*m1-V2*m2
V1 = (V*(m1+m2)+V2*m2)/m1 = (5.89*(1510+2240)+1510*13.2)/2240 = 18.76 m/sec due North
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electron1 say: The first sentence says that 2240 kg car is moving north before the collision. After the collision, both cars are moving north. So let north be the positive direction.

For the 1510 kg car, initial momentum = 1510 * -13.2 = -19,932 kg * m/s
Total mass = 1510 + 2440 = 3750 kg
Final momentum = 3750 * 5.89 = 22,087.5 kg * m/s (North)

For the 2240 kg car, initial momentum = 22,087.5 + -19,932 = 2155.2 kg * m/s

2240 * v = 2155.2
v = 2155.2 ÷ 2240

This is approximately 0.962 m/s north. I hope this is helpful for you.
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