Chemistry HW Help Please (Solutions)
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Chemistry HW Help Please (Solutions)

[From: ] [author: ] [Date: 11-05-05] [Hit: ]
so I dont really care nor need to know this stuff.1.A 12.5-g sample of glucose (C6H12O6) is dissolved in 225 g of water.Calculate the percent by mass of glucose in the solution.2.......
Please don't tell me the whole "I can help you but giving you the answer does nothing for you" comment because to be honest I don't care. I'm 2 weeks away from graduating and I have a 76 C in that class and that's too close to failing. I'm enlisted in the NAVY so no, I won't be going to college, at least any time soon, so I don't really care nor need to know this stuff.

1. A 12.5-g sample of glucose (C6H12O6) is dissolved in 225 g of water. Calculate the percent by mass of glucose in the solution.

2. A chemist prepares some standard solutions for use in the lab using 500.0-mL volumetric flasks to contain the solutions. If the following masses of solutes are used, calculate the resulting molarity of each solution:
a. 4.865 g NaCL b. 78.91 g AgNO3

3. Suppose that each of the following solutions is diluted by adding the indicated amount of water. Calculate the new concentrations of solutions.
a. 255 mL of 3.02 M HCl; 365 mL water added
b. 75.1 g of 1.51% AgNO3; 125 g water added

Thanks in advance

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Good Luck with your NAVY.Remember chemistry will be useful in NAVY too.

Hope these answers will help you to pass the course.

1. % mass of glucose= [mass of glucose /(mass of glucose + water) ] x100= [12.5/( 12.5 + 225)] x100= 5.26
2. a) Molarity= moles/volume= (4.865g/ 58.5g/mol)/.5000L= 0.1663M
b) M= (78.91g/ 169.9g/mol)/.5000L= 0.9289M
3.a) (255 mLx 3.02M) / (365+ 255)mL= 1.24M
b) (75.1 g x 1.51%)/ (75.1 +125)g = 0.567%
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