Calculate the grams of solute required to make the following solutions. Please help. :)

Calculate the grams of solute required to make the following solutions:
1. 2500 g of saline solution (.90%) NaCl (m/m))
b. 0.050 kg of 4.0% (m/m) MgCl2

0.90 (m/m) NaCl = 0.90 g / 100 g. 2500 / 100 = 25. 25 x 0.90
= 22.5 g NaCl.

4.0 g (m/m) MgCl2 = 4.0 g / 100 g. 0.050 kg x 1000 = 50 g.
50 / 100 = 0.5. 0.5 x 4.0 = 2.0 g MgCl2.