How do I calculate the pH of a 2 molar solution of potasium hydroxide and water

I always wanted to mee you banana.
KOH ---> OH- + K+
KOH IS A VERY STRONG ACID THAT MEANS THAT THE CONCENTRATION OF [OH-]=[KOH]=2M
POH=-LOG[OH-]=-LOG[2]=-0.301
PH=14-POH=14-(-0.301=14.301

Just one mistype by Elie D. It should be base rather than "acid" in:

KOH IS A VERY STRONG ACID