Kw problem please help

100 g of lithium hydroxide is dissolved in 750 ml of water.

A) Write the disassociation equation

B) Calculate both [H30+] and [OH-]

I'm confused with this question, please help me out I'd be really happy if you did!

LiOH(s) ----> (Li+)(aq) + (OH-)(aq)

For [OH]:
100g x (1mol/23.95g) = 4.18 moles LiOH(s)
750mL = .750L
4.18 moles/0.750L = 5.567 moles/L = 5.567 M LiOH
Since 1 mole of LiOH produces 1 mole of OH-, [OH-] = 5.567

For [H3O+]:
[H3O+][OH-] = Kw = 1*10^-14
solving for [H30+], I get [H30+] = 5.567*10^14 M