Calculate the molarity of 4.25g of NH3 in 0.500 L of solution, the concentration of NH3 in household ammonia.
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Calculate the molarity of 4.25g of NH3 in 0.500 L of solution, the concentration of NH3 in household ammonia.

[From: ] [author: ] [Date: 11-07-07] [Hit: ]
14 + 3 = 17 grams/mole.4.25 g x1 mole/17 grams = 4.25/17 = 0.25 moles.just divide by volume to get molarity (0.......
PLZ help ASAP !!

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molarity = moles/Liter

to find number of moles you need the molar mass of NH3 which you can calculate from the periodic table (atomic weight). N = 12, H = 1. Since there are 3 H you multiply 1 x 3 = 3. 14 + 3 = 17 grams/mole.

4.25 g x1 mole/17 grams = 4.25/17 = 0.25 moles.

just divide by volume to get molarity (0.5 liters)
0.25 moles/0.5 L = 0.05 M (molarity)

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The previous answer is incorrect. There are 8.5 g NH3/L which is a half of a mole per liter (8.5/17) =0.5. Therefore your solution is 0.5 molar, not 0.05 molar.
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