The phase angle of an LRC series circuit with an inductive reactance of 200 Ω,

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The phase angle of an LRC series circuit with an inductive reactance of 200 Ω,

[From: ] [author: ] [Date: 11-07-07] [Hit: ]

Therefore, C) 119 Ω is theanswer.......

. . .and a capacitive reactance of 100 Ω is 40.0°. What is the value of the resistor in this circuit?
A)200 Ω
B)265 Ω
C)119 Ω
D)100 Ω
E)156 Ω

If you could walk me through the steps, that would be great! Thanks!

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It is 90 - 40 = 50 degree with the resistive Component.

Hence tan 50 = R(Resistive Component),Resistance/ 100
or, R= 1.19*100 = 119 Ω
or, R= 119Ω

Therefore, C) 119 Ω is the answer.

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