Vanillin(used to flavor foods) can be detected at 2.0 x 10-11 g/L of air. If the current price of 50 gr of vanillin is $112, determine the cost to supply enough vanillin so that you would be able to detect it in an aircraft hanger with a volume of 5.0 x 107 ft3. Thanks really appreciate your help!
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use dimensional analysis..
1) sort through the problem and id the fixed amount and the conversion factors
2) start with the fixed value on the left and convert to the right...
3) fill in any missing conversions as you go...
I'm not sure if you really meant to write 50gr is $112.. so.
IF you meant.. 50grains = $112.. then.
5.0x10^7ft³ x (12in / 1ft)³ x (2.54cm / 1in)³ x (1mL / 1cm³) x (1L / 1000mL) x (2.0x10^-11g / L) x (1gr / 64.80g) x ($112 / 50 gr) = $0.00098
IF you meant 50 grams = $112, then
5.0x10^7ft³ x (12in / 1ft)³ x (2.54cm / 1in)³ x (1mL / 1cm³) x (1L / 1000mL) x (2.0x10^-11g / L) x ($112 / 50 gr) = $0.063
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do you understand?
1) sort through the problem and id the fixed amount and the conversion factors
2) start with the fixed value on the left and convert to the right...
3) fill in any missing conversions as you go...
I'm not sure if you really meant to write 50gr is $112.. so.
IF you meant.. 50grains = $112.. then.
5.0x10^7ft³ x (12in / 1ft)³ x (2.54cm / 1in)³ x (1mL / 1cm³) x (1L / 1000mL) x (2.0x10^-11g / L) x (1gr / 64.80g) x ($112 / 50 gr) = $0.00098
IF you meant 50 grams = $112, then
5.0x10^7ft³ x (12in / 1ft)³ x (2.54cm / 1in)³ x (1mL / 1cm³) x (1L / 1000mL) x (2.0x10^-11g / L) x ($112 / 50 gr) = $0.063
***********
do you understand?