What is the limit of (x^2-x+12)/(x+3) with x --> -3

lim (x^2-x+12)/(x+3)
x --> -3

Help?

I'd consider using quadratic formula on numerator(x^2-x+12) but you won't get any answer because the number gets negative while solving quadratic. you also get 0 at denominator (when you put -3 in x for x+3). stay tuned...i'm still working on it ;) btw do you know the answer?


EDIT: I tried my best but i believe that the limit does not exist because of numerator not getting a balanced factorization. look below

-b(+-) (square root of b^2-4*a*c)/2*a
-(-1) (+-) (square root of (-1)^2-4*1*12)/ 2*1
the answer is 1(+-) (square root of 1-48)/2
which gives 1(+-) (square root of -47)/2
You cannot take square root of -47, its not possible.
My conclusion is that there are no limit. You can ask your teacher, its ok to ask because these are one the signs of you being smart ;)

it is not an indeterminate form. may be a typo. so let me consider x^2-x-12 instead. method 1. use l'hospital, 2x-1/1 ie 2(-3)-1 ie -7. method 2. x^2-x-12 is (x-4)(x+3), cancel x+3 on both giving u x-4 ie -3-4 ie -7