Half life...chemistry please :)
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Half life...chemistry please :)

[From: ] [author: ] [Date: 11-08-18] [Hit: ]
3 days. If you currenlt have 17.9 g of 32P, how much 32P was present 2.00 days ago?______g.......
(1) After 9.00 days, 46.0% of a sample of 131I remains. What is the half-life of 131I?
_______ days


(2) The half-life 32P is 14.3 days. If you currenlt have 17.9 g of 32P, how much 32P was present 2.00 days ago?
______g.


please show the steps thank you again so much!!! you guys have no idea how much this means to me!! all your help has been great :)

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A(t)/A(0) = e^(- ln 2 x t/T1/2) = (1/2) t/T1/2
0.46 / 1 = e^(-ln2 x 9/T1/2)
0.46 = e^(-0.693 x 9/T1/2)
ln0.46 = -0.693 x 9/T1/2
-0.776 = -6.237 / T1/2
T1/2 = -6.237 / -0.776 = 8.03days

T1/2 = 14.3days
17.9g / [32Pº] = e^(-0.693 x 2/14.3)
17.9g / [32Pº] = e^-0.097
17.9g / e^-0.097 = [32Pº] = 19.72g
1
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