Can someone please explain this chem problem to me

A 23.2 g sample of ore that contains the mineral corundum is found to contain 14.2 g of aluminum. The element aluminum is 62.776 percent by mass of the mineral corundum. Calculate the percent by mass of the mineral corundum in the ore.

thank you!!

(Assuming corundum is the only source of aluminum in the ore)
Divide the 14.2 g Al by .62776 to find the mass of corundum in the ore.

Then divide that answer by 23.2 g to find the decimal fraction (by mass) of corundum in the sample.

Finally, multiply by 100 to change the decimal fraction to percent. There are three significant figures in the answer.