What is [pOH] and [H3O+]

[OH-] = 9.1 x 10^-2

pH = 12

[pOH] = _____ ?

[H3O+] = _____ ?

Please show your work. Thanks!

[OH-] = 9.1 x 10^-2
pOH = - log of [9.1 x 10^-2]
so pOH = 1.04

p.s.
since the pH + pOH = 14,.... the pH = 12.96
& since [H+] = 10^-12.96 the [H3O+] = 1.1 X 10^-13 Molar

===========================

pH = 12

[H3O+] = 10^-12
so [H3O+] = 1 X 10-12 Molar


p.s
since pH + pOH = 14,.... the pOH = 2
& since the [OH-] = 10^-2,..... [[OH-] = 1 x 10^-2 Molar