How much 50% wt/wt NaOH (in mL) do I need to make 1 liter of 0.100 M solution?
Thanks a tonne! :)
Thanks a tonne! :)

The molecular weight of NaOH is 40 so if you make 1 liter of 0.1 Molar solution
you will need 0.1 mole, or 4.0 grams of NaOH in solution.
If your stock solution of NaOH is 50% by weight, you will need 8 grams of stock
solution, which will contain 4.0 grams of sodium hydroxide. That is the mass,
not the volume, of solution you will need. To find the volume of solution you need
to know the density of the stock solution which is not given here.
If you know the density D you can find the volume V needed by the formula:
V = M/D and you know that you need a mass of 8 grams of solution.
So divide 8 grams by the density of solution (in grams per ml.) and you will
have the required volume in ml.
you will need 0.1 mole, or 4.0 grams of NaOH in solution.
If your stock solution of NaOH is 50% by weight, you will need 8 grams of stock
solution, which will contain 4.0 grams of sodium hydroxide. That is the mass,
not the volume, of solution you will need. To find the volume of solution you need
to know the density of the stock solution which is not given here.
If you know the density D you can find the volume V needed by the formula:
V = M/D and you know that you need a mass of 8 grams of solution.
So divide 8 grams by the density of solution (in grams per ml.) and you will
have the required volume in ml.