How do you determine the molar mass in this problem

A solution was made by dissolving 3.75g of a nonvolatile solute in 108.7g of acetone. The solution boiled at 56.58 degrees C. The boiling point of pure acetone is 55.95 degrees C and K = 1.71 degrees C/m.

Thanks! :)

Mass of solute in 1kg acetone = 3.75*1000/108.7 = 34.4986g

Boiling point was raised by 56.58 - 55.95 = 0.63°C
1molal solution will increase the boiling point by 1.71°C
Therefore you have 0.63/1.71 = 0.368 mol in solution

Molar mass solute = 34.4986/0.368 = 93.64g/mol