64L^1/4
Please, help me to recognize if is a maximum or a minimum.
Please, help me to recognize if is a maximum or a minimum.
-
The function (assumed real) is defined only for L ≥ 0.
d/dL(64 L^¼) = ¼ * 64 L^(-¾) = 16 L^(-¾)
Since L ≥ 0, the derivative is positive for all L in the domain. This means the function is everywhere increasing. It has an absolute minimum of 0 at L = 0, and (in the absence of a restriction on the upper value of L) has no maximum; it grows arbitrarily large as L grows arbitrarily large.
d/dL(64 L^¼) = ¼ * 64 L^(-¾) = 16 L^(-¾)
Since L ≥ 0, the derivative is positive for all L in the domain. This means the function is everywhere increasing. It has an absolute minimum of 0 at L = 0, and (in the absence of a restriction on the upper value of L) has no maximum; it grows arbitrarily large as L grows arbitrarily large.