Calculate the pH of a buffer solution that is .75M NH3 and .45M NH4Cl
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Calculate the pH of a buffer solution that is .75M NH3 and .45M NH4Cl

[From: ] [author: ] [Date: 11-10-25] [Hit: ]
45/0.75)= 4.pH= 14-pOH = 9.I hope this helps and feel free to send me an e-mail if you have any doubts!......
Use the Henderson-Hasselbalch equation. pKb NH3= 4.75

Please show all work!! Thanks a bunch! :D

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pOH= pKb+lg([NH4(+)]/[NH3])
= 4.75+lg(0.45/0.75)
= 4.53

pH= 14-pOH
= 9.47

I hope this helps and feel free to send me an e-mail if you have any doubts!
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