How many moles of NaOH are there in 7.0 mL of 6.0M NaOH

in liters using the equation A=MA X V

or

MA =number of moles of A/ number of liters of solution, V? Thanks

How many moles of NaOH are there in 7.0 mL of 6.0M NaOH?
in liters using the equation A=MA X V

or

MA =number of moles of A/ number of liters of solution, V? Thanks

MA=A/XV
-> 6.0m/L * 0.007L = 0.042 m NaOH

0.042m / 0.400L= 0.105M

6.0 M means 6.0 moles per liter.
Convert 7.0 mL into liters ----> .0070 L
Now, multiply.
6.0 moles/L * .0070L = .042 moles

Basically, look at the units you have and the units you want and line it up so unnecessary units cancel out.

1. Convert 7.0mL to L - 7.0mL*(1L/1000mL)=0.0070 L
2. Change 6.0M to 6.0 mole/L
3. Multiply 6.0 mole/L by 0.0070L
4. Then it will result to 0.042 moles

7.0 ml (6.0 mol NaOH/ 1000 ml) = .042 mol NaOH