Calculate the mass of ammonium chloride produced and the amount of ammonium chloride which reacts

25.00 mL of 2.00 mol/L sodium hydroxide was boiled with excess ammonium chloride. calculate:
(a) the mass of ammonium chloride which reacts
AND
(b) the volume of ammonia produced at S.T.P

NaOH + NH4Cl --> NaCl + H2O + NH3
0.025L x 2M = 0.05moles NaOH
0.05moles NaOH requires 0.05moles NH4Cl = 2.67g NH4Cl reacts

0.05moles NH3 produced x 22.4L/mole = 1.12L

(a) 1.7 gm
(b)1.12 litre