Considering the most common oxidation states of Ba and N, which compound would be formed by
the reaction of Ba and N?
I know the answer is Ba3N2, but I don't understand how to get there. Thanks in advance.
the reaction of Ba and N?
I know the answer is Ba3N2, but I don't understand how to get there. Thanks in advance.
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The common oxidation state of Ba is +2, and for N it is -3. If you want these atoms to get together, the overall charge should be 0. The way to do this is to have 3 Ba for every 2 N, because 3(+2) = 6, which balances 2(-3) = -6.
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Ba has 2 electrons to donate, from its outer shell of 3s2 amd Nitrogen has five electrons in its outer shell. 2s2, and 2p3. The valences are Ba^2+ and N ^3- Formula is Ba3N2.
3 baariums donated 6electrons and the 2 nitrogens received the 6 electrons to fill both orbitals.
3 baariums donated 6electrons and the 2 nitrogens received the 6 electrons to fill both orbitals.
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Common oxidation state is +2 and nitrogen is 3
hence +2 -3
Ba N
cross them
Ba3N2
hence +2 -3
Ba N
cross them
Ba3N2