Algebra 1 help!! please! =D

6. Evaluate the expression 4x^2y^3 when x=1/2 and y=-2

a. -4
b. -8
c. -16

Plug in 1/2 where you see x and -2 when you see y

so your equation is"

I'm writing 1/2 as .5 to make it easier to read

4(.5^2)-2^3

.5^2 = .25 or 1/4

-2^3 = -2 x -2 x -2 = 4 x -2 = -8

new equation is:

4 x .25 x -8


-8 x 4 = -32

-32 x .25 (or 1/4) = -8

-8 is your answer

4(1/2)²(-2)³
4(1/4)(-8)
-8