How many liters of CO2 gas at STP will contain 1137 molecules

[From: ] [author: ] [Date: 12-07-07] [Hit: ]

414 L/mol) = 4.231 × 10^-20 L-at STP 6.023 *10^23 molecules are contained by 22.4 litres so 1137 molecules are contained by 22.4/A*1137 [ A is the avogadro number that is 6.023.......

I do not understand the steps involved in this. This is the least explained concept in my book! I know 1 mole is 6.02 x 10^23. I know one mole = 22.4L. I'm solving for L? Where in the world do I even begin. :(

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(1137 molecules) / (6.023 × 10^23 molecules/mol) × (22.414 L/mol) = 4.231 × 10^-20 L

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at STP 6.023 *10^23 molecules are contained by 22.4 litres
so 1137 molecules are contained by 22.4/A*1137 [ A is the avogadro number that is 6.023....]
ans- 4.22 *10^-20 litres

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