What is the length of the antenna

This is a trigonometry problem and it says: When the angle of elevation to the sun is 73 degrees, and antenna tilted at an angle of 6 degrees away from the sun casts a shodow 155 feet long. Determine the length of the antenna. The answer I got was about 155 feet long but I am not sure if that is correct... I basically put 155sin(73)/ sin(101) = 151.001. Please help!!!!!!

Assuming level ground, the line from the foot of the antenna to the shadow of the tip is 155 feet.
This line, the antenna and the line of sight joining the tip of the antenna to the shadow of the tip from a triangle, say ABC, where
A is the foot of the antenna, B is the end of the shadow, and C is the top of the antenna.
AB = 155
< ABC = 73 degrees.
which implies < BCA = 180 - (84 + 73) = 23 degrees

AC / sin 73 = AB / sin 23

101 degrees is not a measure of any angle in the triangle.

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Sketch a triangle. The base is 115 ft. The interior angle on the right is 73 degrees. The other side (the flagpole) is not quite vertical, it leans to the right 6 degrees, so the interior angle is 84 degrees. The other angle is 180-84-73 degrees, or 23 degrees. Let x be the length of the flagpole.

Use the Law of Sines:

x/sin(73) = 115/sin(23)

x = 115 * sin(73)/sin(23)

x is approximately 281.4596507

If my explanation was not clear then look at this link:

http://tinypic.com/r/123oyo8/6