So I have 2 resistors connected in series with an ac source. The supply voltage that I measured is 40v. I measured 20v across each capacitor. Would the relation V=IR still hold , even though it is an ac circuit ?
Are the voltages across each resistor in phase ?
Are the voltages across each resistor in phase ?
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U is voltage.
u(t) is instant voltage which is a function of time.
u(t)=Umax * sin(wt+theta)
where w = 2 pi f
where f=frequency
how many capacitors and how are they put in the circuit.
normaly the law is U=ZI
U=Umax / sqrt 2
Z=sqrt [R^2 +(XL-XC)^2] in series
or Z=1/ sqrt [ 1/R^2 + 1/(XL-XC)^2 ] in parallel
You don't have XL so you equal XL to 0
XC=1/wC
where C is the capacitance of the capacitor
Tan (theta) = (XL-XC ) /R
and from here you find theta.
Anyhow you have to give more data about the circuit.
u(t) is instant voltage which is a function of time.
u(t)=Umax * sin(wt+theta)
where w = 2 pi f
where f=frequency
how many capacitors and how are they put in the circuit.
normaly the law is U=ZI
U=Umax / sqrt 2
Z=sqrt [R^2 +(XL-XC)^2] in series
or Z=1/ sqrt [ 1/R^2 + 1/(XL-XC)^2 ] in parallel
You don't have XL so you equal XL to 0
XC=1/wC
where C is the capacitance of the capacitor
Tan (theta) = (XL-XC ) /R
and from here you find theta.
Anyhow you have to give more data about the circuit.