Trig Problem solving in terms of pi

[From: ] [author: ] [Date: 11-05-16] [Hit: ]

Interval of [0,2pi) terms of pi

5tan^2-15=0
tan^2x=3
tanx=sqt3
This is as far as ive got please help

tan^2x=3
=> tanx = +/- sqrt(3)
x = pi/3, 2pi/3, 4pi/3, 5pi/3

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