perform the operations and simplify: 1/ x-y - 2x/x^2-y^2+1/x+y
how do i solve this-please show answer and work,thanks!
how do i solve this-please show answer and work,thanks!
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The first thing to do is simplify the fractions so the term -2x/x^2 becomes -2/x. Next combine all the terms that you can so terms with the same variable and power. There are two 1/x terms so they become 2/x and there is the -2/x that was simplified earlier so those cancel. Next there is a -y and a y so they cancel and what's left is -y^2.
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Oh if there was only supposed to be three terms then it's something totally different but the answer in my explanation is how the calculator would read it.
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1/(x-y) -2x/(x^2-y^2) + 1/(x+y)
1/(x-y) -2x/((x+y)(x-y)) +1/(x+y)
(x+y)/((x+y)(x-y)) -2x/((x+y)(x-y)) +(x-y)/((x+y)(x-y))
(x+y-2x+x-y)/((x+y)(x-y))
0/((x+y)(x-y))
0
1/(x-y) -2x/((x+y)(x-y)) +1/(x+y)
(x+y)/((x+y)(x-y)) -2x/((x+y)(x-y)) +(x-y)/((x+y)(x-y))
(x+y-2x+x-y)/((x+y)(x-y))
0/((x+y)(x-y))
0