Calculus Partial Derivatives

Find the partial derivatives of ((108xy-x^2y^2)/(2(x+y))

in respect to x_______________

and in respect to y_____________________

Please necessary work. Thanks

f(x,y) = (108xy - x^2y^2)/(2(x+y)

∂f/∂x = -(y^2 (x^2 + 2xy - 108))/(2(x+y)^2)

∂f/∂y = -(x^2 (2xy + y^2 - 108))/(2(x+y)^2)

you gotta use quotient or product rule man

sorry... lol