Find the x-intercept and the y-intercept in the line.

Find the x-intercept and the y-intercept in the line.
4y=24-12x

Write the equation in slope-intercept form.
2y-6x=-10

Find the slope and y-intercept.
y=3x-5

Which equation is for the line that passes through (-2, 2) and (4, -4)?

Equations:
A) 4y=24 - 12x
B) 2y-6x = -10

Divide equation (A) by 4 to obtain:
y = 6 -3x

The y intercept occurs when x equals 0. therefore the y intercept is at y= 6- 3*0=6
The x intercept occurs when y equals 0. therefore the x intercept is at 0 = 6- 3x
x = 2

For equation (B) simply divide by 2 and add 3x to both sides (of the equation) to obtain:
y = 3x -5
'3' is the slope and '-5' is the y intercept.

*Note: if an equation Y = aX + b the slope equals 'a' and the y-intercept equals 'b'.

for the equation of the line that goes through (-2, 2) and (4, -4) it is y = -x . (because the slope is -1)

Ax + By = C
C/A = x-intercept
C/B = y-intercept


slope-intercept form is
y=mx + b


y = mx + b
m is the slope of the line
b is the y-intercept


Find the slope (m) of the line that connects (-2 , 2) and (4 , -4).
To find the y-intercept (b) you can do either of these two things:
1.
2m + 2 = b
2.
-4 - 4m = b