Find the slope of the tangent line on circle Q at point P (2,6)

The center if the circle, Q, is (5,1)

Thanks

The tangent line will be perpendicular to the radius. The radial line from the center (5, 1) to the point (2, 6) on the circle has slope (rise over run)

(6 - 1)/(2 - 5) = 5/(-3) = - 2.

The tangent line has slope 1/2 (negative reciprocal.)