many different passwords are possible if digits and letters CAN be repeated.
Please help me with this math problem. I'm not exactly how to solve this.
Please help me with this math problem. I'm not exactly how to solve this.

You multiply 9x10x10x26x26 which equals 608400. This is correct because you have 9 choices (1,2,3,4,5,6,7,8,9) for the first digit, 10 choices (1,2,3,4,5,6,7,8,9,0) for the second digit, 10 choices (1,2,3,4,5,6,7,8,9,0) for the third digit, 26 choices (a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t… for the first letter, and 26 choices (a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t… for the second letter. Multiplying your total number of options together gives you the answer.

Your first number then has to be 19 so that is 9 possibilities
the second number can be 09 so that is 10 possibilities,
the third number can be 09 also so that is 10 possibilities
the fourth letter can be az so that is 26 possibilities
the fifth also can be az so that is also 26 possibilities.
Multiply 9x10x10x26x26 to get your answer
the second number can be 09 so that is 10 possibilities,
the third number can be 09 also so that is 10 possibilities
the fourth letter can be az so that is 26 possibilities
the fifth also can be az so that is also 26 possibilities.
Multiply 9x10x10x26x26 to get your answer

first digit:19
second digit:09
third digit:09
letter 1:26
letter 2:26
9*10*10*26*26=608,400 passwords
second digit:09
third digit:09
letter 1:26
letter 2:26
9*10*10*26*26=608,400 passwords

9*10*10*26*26= 608400 possibilities