A website password must include 3 digits followed 2 letters. The first digit cannot be 0. How

many different passwords are possible if digits and letters CAN be repeated.


Please help me with this math problem. I'm not exactly how to solve this.

You multiply 9x10x10x26x26 which equals 608400. This is correct because you have 9 choices (1,2,3,4,5,6,7,8,9) for the first digit, 10 choices (1,2,3,4,5,6,7,8,9,0) for the second digit, 10 choices (1,2,3,4,5,6,7,8,9,0) for the third digit, 26 choices (a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t… for the first letter, and 26 choices (a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t… for the second letter. Multiplying your total number of options together gives you the answer.

Your first number then has to be 1-9 so that is 9 possibilities
the second number can be 0-9 so that is 10 possibilities,
the third number can be 0-9 also so that is 10 possibilities
the fourth letter can be a-z so that is 26 possibilities
the fifth also can be a-z so that is also 26 possibilities.
Multiply 9x10x10x26x26 to get your answer

first digit:1-9
second digit:0-9
third digit:0-9
letter 1:26
letter 2:26
9*10*10*26*26=608,400 passwords

9*10*10*26*26= 608400 possibilities